bootstrap-vz/common/tools.py
Anders Ingemann a60715e710 Simplify sed_i by using fileinput module
This also fixes the problem with the owner:group being set to root
2013-11-22 09:03:48 +01:00

50 lines
1.5 KiB
Python

def log_check_call(command, stdin=None):
status, stdout, stderr = log_call(command, stdin)
if status != 0:
from subprocess import CalledProcessError
raise CalledProcessError(status, ' '.join(command), '\n'.join(stderr))
return stdout
def log_call(command, stdin=None):
import subprocess
import select
import logging
from os.path import realpath
command_log = realpath(command[0]).replace('/', '.')
log = logging.getLogger(__name__ + command_log)
log.debug('Executing: {command}'.format(command=' '.join(command)))
if stdin is not None:
process = subprocess.Popen(command, stdin=subprocess.PIPE, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
process.stdin.write(stdin + "\n")
process.stdin.flush()
process.stdin.close()
else:
process = subprocess.Popen(command, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
stdout = []
stderr = []
while True:
reads = [process.stdout.fileno(), process.stderr.fileno()]
ret = select.select(reads, [], [])
for fd in ret[0]:
if fd == process.stdout.fileno():
for line in iter(process.stdout.readline, ''):
log.debug(line.strip())
stdout.append(line.strip())
if fd == process.stderr.fileno():
for line in iter(process.stderr.readline, ''):
log.error(line.strip())
stderr.append(line.strip())
if process.poll() is not None:
return process.returncode, stdout, stderr
def sed_i(file_path, pattern, subst):
import fileinput
import re
for line in fileinput.input(files=file_path, inplace=True):
print re.sub(pattern, subst, line),